Metamath Proof Explorer


Theorem ac6s6f

Description: Generalization of the Axiom of Choice to classes, moving the existence condition in the consequent. (Contributed by Giovanni Mascellani, 20-Aug-2018)

Ref Expression
Hypotheses ac6s6f.1 ⊢ A ∈ V
ac6s6f.2 ⊢ Ⅎ y ψ
ac6s6f.3 ⊢ y = f ⁡ x → φ ↔ ψ
ac6s6f.4 ⊢ Ⅎ _ x A
Assertion ac6s6f ⊢ ∃ f ∀ x ∈ A ∃ y φ → ψ

Proof

Step Hyp Ref Expression
1 ac6s6f.1 ⊢ A ∈ V
2 ac6s6f.2 ⊢ Ⅎ y ψ
3 ac6s6f.3 ⊢ y = f ⁡ x → φ ↔ ψ
4 ac6s6f.4 ⊢ Ⅎ _ x A
5 1 isseti ⊢ ∃ z z = A
6 vex ⊢ z ∈ V
7 2 6 3 ac6s6 ⊢ ∃ f ∀ x ∈ z ∃ y φ → ψ
8 5 7 exan ⊢ ∃ z z = A ∧ ∃ f ∀ x ∈ z ∃ y φ → ψ
9 exdistr ⊢ ∃ z ∃ f z = A ∧ ∀ x ∈ z ∃ y φ → ψ ↔ ∃ z z = A ∧ ∃ f ∀ x ∈ z ∃ y φ → ψ
10 8 9 mpbir ⊢ ∃ z ∃ f z = A ∧ ∀ x ∈ z ∃ y φ → ψ
11 nfcv ⊢ Ⅎ _ x z
12 11 4 raleqf ⊢ z = A → ∀ x ∈ z ∃ y φ → ψ ↔ ∀ x ∈ A ∃ y φ → ψ
13 12 biimpa ⊢ z = A ∧ ∀ x ∈ z ∃ y φ → ψ → ∀ x ∈ A ∃ y φ → ψ
14 13 2eximi ⊢ ∃ z ∃ f z = A ∧ ∀ x ∈ z ∃ y φ → ψ → ∃ z ∃ f ∀ x ∈ A ∃ y φ → ψ
15 ax5e ⊢ ∃ z ∃ f ∀ x ∈ A ∃ y φ → ψ → ∃ f ∀ x ∈ A ∃ y φ → ψ
16 10 14 15 mp2b ⊢ ∃ f ∀ x ∈ A ∃ y φ → ψ