Metamath Proof Explorer


Theorem ac6s6f

Description: Generalization of the Axiom of Choice to classes, moving the existence condition in the consequent. (Contributed by Giovanni Mascellani, 20-Aug-2018)

Ref Expression
Hypotheses ac6s6f.1 ⊢ 𝐴 ∈ V
ac6s6f.2 ⊢ Ⅎ 𝑦 𝜓
ac6s6f.3 ⊢ ( 𝑦 = ( 𝑓 ‘ 𝑥 ) → ( 𝜑 ↔ 𝜓 ) )
ac6s6f.4 ⊢ Ⅎ 𝑥 𝐴
Assertion ac6s6f ∃ 𝑓 ∀ 𝑥 ∈ 𝐴 ( ∃ 𝑦 𝜑 → 𝜓 )

Proof

Step Hyp Ref Expression
1 ac6s6f.1 ⊢ 𝐴 ∈ V
2 ac6s6f.2 ⊢ Ⅎ 𝑦 𝜓
3 ac6s6f.3 ⊢ ( 𝑦 = ( 𝑓 ‘ 𝑥 ) → ( 𝜑 ↔ 𝜓 ) )
4 ac6s6f.4 ⊢ Ⅎ 𝑥 𝐴
5 1 isseti ⊢ ∃ 𝑧 𝑧 = 𝐴
6 vex ⊢ 𝑧 ∈ V
7 2 6 3 ac6s6 ⊢ ∃ 𝑓 ∀ 𝑥 ∈ 𝑧 ( ∃ 𝑦 𝜑 → 𝜓 )
8 5 7 exan ⊢ ∃ 𝑧 ( 𝑧 = 𝐴 ∧ ∃ 𝑓 ∀ 𝑥 ∈ 𝑧 ( ∃ 𝑦 𝜑 → 𝜓 ) )
9 exdistr ⊢ ( ∃ 𝑧 ∃ 𝑓 ( 𝑧 = 𝐴 ∧ ∀ 𝑥 ∈ 𝑧 ( ∃ 𝑦 𝜑 → 𝜓 ) ) ↔ ∃ 𝑧 ( 𝑧 = 𝐴 ∧ ∃ 𝑓 ∀ 𝑥 ∈ 𝑧 ( ∃ 𝑦 𝜑 → 𝜓 ) ) )
10 8 9 mpbir ⊢ ∃ 𝑧 ∃ 𝑓 ( 𝑧 = 𝐴 ∧ ∀ 𝑥 ∈ 𝑧 ( ∃ 𝑦 𝜑 → 𝜓 ) )
11 nfcv ⊢ Ⅎ 𝑥 𝑧
12 11 4 raleqf ⊢ ( 𝑧 = 𝐴 → ( ∀ 𝑥 ∈ 𝑧 ( ∃ 𝑦 𝜑 → 𝜓 ) ↔ ∀ 𝑥 ∈ 𝐴 ( ∃ 𝑦 𝜑 → 𝜓 ) ) )
13 12 biimpa ⊢ ( ( 𝑧 = 𝐴 ∧ ∀ 𝑥 ∈ 𝑧 ( ∃ 𝑦 𝜑 → 𝜓 ) ) → ∀ 𝑥 ∈ 𝐴 ( ∃ 𝑦 𝜑 → 𝜓 ) )
14 13 2eximi ⊢ ( ∃ 𝑧 ∃ 𝑓 ( 𝑧 = 𝐴 ∧ ∀ 𝑥 ∈ 𝑧 ( ∃ 𝑦 𝜑 → 𝜓 ) ) → ∃ 𝑧 ∃ 𝑓 ∀ 𝑥 ∈ 𝐴 ( ∃ 𝑦 𝜑 → 𝜓 ) )
15 ax5e ⊢ ( ∃ 𝑧 ∃ 𝑓 ∀ 𝑥 ∈ 𝐴 ( ∃ 𝑦 𝜑 → 𝜓 ) → ∃ 𝑓 ∀ 𝑥 ∈ 𝐴 ( ∃ 𝑦 𝜑 → 𝜓 ) )
16 10 14 15 mp2b ⊢ ∃ 𝑓 ∀ 𝑥 ∈ 𝐴 ( ∃ 𝑦 𝜑 → 𝜓 )