Metamath Proof Explorer


Theorem bdaybndbday

Description: Bounds formed from the birthday have the same birthday. (Contributed by RP, 30-Sep-2023)

Ref Expression
Assertion bdaybndbday ⊢ A ∈ No ∧ B = bday ⁡ A ∧ C ∈ 1 𝑜 2 𝑜 → bday ⁡ B × C = bday ⁡ A

Proof

Step Hyp Ref Expression
1 bdaybndex ⊢ A ∈ No ∧ B = bday ⁡ A ∧ C ∈ 1 𝑜 2 𝑜 → B × C ∈ No
2 bdayval ⊢ B × C ∈ No → bday ⁡ B × C = dom ⁡ B × C
3 1 2 syl ⊢ A ∈ No ∧ B = bday ⁡ A ∧ C ∈ 1 𝑜 2 𝑜 → bday ⁡ B × C = dom ⁡ B × C
4 simp3 ⊢ A ∈ No ∧ B = bday ⁡ A ∧ C ∈ 1 𝑜 2 𝑜 → C ∈ 1 𝑜 2 𝑜
5 snnzg ⊢ C ∈ 1 𝑜 2 𝑜 → C ≠ ∅
6 dmxp ⊢ C ≠ ∅ → dom ⁡ B × C = B
7 4 5 6 3syl ⊢ A ∈ No ∧ B = bday ⁡ A ∧ C ∈ 1 𝑜 2 𝑜 → dom ⁡ B × C = B
8 simp2 ⊢ A ∈ No ∧ B = bday ⁡ A ∧ C ∈ 1 𝑜 2 𝑜 → B = bday ⁡ A
9 3 7 8 3eqtrd ⊢ A ∈ No ∧ B = bday ⁡ A ∧ C ∈ 1 𝑜 2 𝑜 → bday ⁡ B × C = bday ⁡ A