Metamath Proof Explorer


Theorem bdaybndbday

Description: Bounds formed from the birthday have the same birthday. (Contributed by RP, 30-Sep-2023)

Ref Expression
Assertion bdaybndbday ANoB=bdayAC1𝑜2𝑜bdayB×C=bdayA

Proof

Step Hyp Ref Expression
1 bdaybndex ANoB=bdayAC1𝑜2𝑜B×CNo
2 bdayval B×CNobdayB×C=domB×C
3 1 2 syl ANoB=bdayAC1𝑜2𝑜bdayB×C=domB×C
4 simp3 ANoB=bdayAC1𝑜2𝑜C1𝑜2𝑜
5 snnzg C1𝑜2𝑜C
6 dmxp CdomB×C=B
7 4 5 6 3syl ANoB=bdayAC1𝑜2𝑜domB×C=B
8 simp2 ANoB=bdayAC1𝑜2𝑜B=bdayA
9 3 7 8 3eqtrd ANoB=bdayAC1𝑜2𝑜bdayB×C=bdayA