Metamath Proof Explorer


Theorem bdaybndbday

Description: Bounds formed from the birthday have the same birthday. (Contributed by RP, 30-Sep-2023)

Ref Expression
Assertion bdaybndbday A No B = bday A C 1 𝑜 2 𝑜 bday B × C = bday A

Proof

Step Hyp Ref Expression
1 bdaybndex A No B = bday A C 1 𝑜 2 𝑜 B × C No
2 bdayval B × C No bday B × C = dom B × C
3 1 2 syl A No B = bday A C 1 𝑜 2 𝑜 bday B × C = dom B × C
4 simp3 A No B = bday A C 1 𝑜 2 𝑜 C 1 𝑜 2 𝑜
5 snnzg C 1 𝑜 2 𝑜 C
6 dmxp C dom B × C = B
7 4 5 6 3syl A No B = bday A C 1 𝑜 2 𝑜 dom B × C = B
8 simp2 A No B = bday A C 1 𝑜 2 𝑜 B = bday A
9 3 7 8 3eqtrd A No B = bday A C 1 𝑜 2 𝑜 bday B × C = bday A