Metamath Proof Explorer


Theorem bj-axc10

Description: Alternate proof of axc10 . Shorter. One can prove a version with DV ( x , y ) without ax-13 , by using ax6ev instead of ax6e . (Contributed by BJ, 31-Mar-2021) (Proof modification is discouraged.)

Ref Expression
Assertion bj-axc10 ⊢ ∀ x x = y → ∀ x φ → φ

Proof

Step Hyp Ref Expression
1 ax6e ⊢ ∃ x x = y
2 exim ⊢ ∀ x x = y → ∀ x φ → ∃ x x = y → ∃ x ∀ x φ
3 1 2 mpi ⊢ ∀ x x = y → ∀ x φ → ∃ x ∀ x φ
4 axc7e ⊢ ∃ x ∀ x φ → φ
5 3 4 syl ⊢ ∀ x x = y → ∀ x φ → φ