Metamath Proof Explorer


Theorem bj-axc14

Description: Alternate proof of axc14 (even when inlining the above results, this gives a shorter proof). (Contributed by BJ, 20-Oct-2021) (Proof modification is discouraged.)

Ref Expression
Assertion bj-axc14 ⊢ ¬ ∀ z z = x → ¬ ∀ z z = y → x ∈ y → ∀ z x ∈ y

Proof

Step Hyp Ref Expression
1 bj-axc14nf ⊢ ¬ ∀ z z = x → ¬ ∀ z z = y → Ⅎ z x ∈ y
2 nf5r ⊢ Ⅎ z x ∈ y → x ∈ y → ∀ z x ∈ y
3 2 a1i ⊢ ¬ ∀ z z = x → Ⅎ z x ∈ y → x ∈ y → ∀ z x ∈ y
4 1 3 syld ⊢ ¬ ∀ z z = x → ¬ ∀ z z = y → x ∈ y → ∀ z x ∈ y