Metamath Proof Explorer


Theorem bj-axc14nf

Description: Proof of a version of axc14 using the "nonfree" idiom. (Contributed by BJ, 20-Oct-2021) (Proof modification is discouraged.)

Ref Expression
Assertion bj-axc14nf ⊢ ¬ ∀ z z = x → ¬ ∀ z z = y → Ⅎ z x ∈ y

Proof

Step Hyp Ref Expression
1 bj-nfeel2 ⊢ ¬ ∀ z z = x → Ⅎ z x ∈ t
2 elequ2 ⊢ t = y → x ∈ t ↔ x ∈ y
3 1 2 bj-dvelimdv1 ⊢ ¬ ∀ z z = x → ¬ ∀ z z = y → Ⅎ z x ∈ y