Description: Disjointness of the singletons containing 0 and 1. This is a consequence of disjcsn but the present proof does not use regularity. (Contributed by BJ, 4-Apr-2019) (Proof modification is discouraged.)
Ref | Expression | ||
---|---|---|---|
Assertion | bj-disjsn01 | |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | 1n0 | |
|
2 | 1 | necomi | |
3 | disjsn2 | |
|
4 | 2 3 | ax-mp | |