Metamath Proof Explorer


Theorem bj-disjsn01

Description: Disjointness of the singletons containing 0 and 1. This is a consequence of disjcsn but the present proof does not use regularity. (Contributed by BJ, 4-Apr-2019) (Proof modification is discouraged.)

Ref Expression
Assertion bj-disjsn01 1𝑜=

Proof

Step Hyp Ref Expression
1 1n0 1𝑜
2 1 necomi 1𝑜
3 disjsn2 1𝑜1𝑜=
4 2 3 ax-mp 1𝑜=