Metamath Proof Explorer


Theorem bj-inrab2

Description: Shorter proof of inrab . (Contributed by BJ, 21-Apr-2019) (Proof modification is discouraged.)

Ref Expression
Assertion bj-inrab2 ⊢ x ∈ A | φ ∩ x ∈ A | ψ = x ∈ A | φ ∧ ψ

Proof

Step Hyp Ref Expression
1 bj-inrab ⊢ x ∈ A | φ ∩ x ∈ A | ψ = x ∈ A ∩ A | φ ∧ ψ
2 nfv ⊢ Ⅎ x ⊤
3 inidm ⊢ A ∩ A = A
4 3 a1i ⊢ ⊤ → A ∩ A = A
5 2 4 rabeqd ⊢ ⊤ → x ∈ A ∩ A | φ ∧ ψ = x ∈ A | φ ∧ ψ
6 5 mptru ⊢ x ∈ A ∩ A | φ ∧ ψ = x ∈ A | φ ∧ ψ
7 1 6 eqtri ⊢ x ∈ A | φ ∩ x ∈ A | ψ = x ∈ A | φ ∧ ψ