Metamath Proof Explorer


Theorem bj-rexcom4bv

Description: Version of rexcom4b and bj-rexcom4b with a disjoint variable condition on x , V , hence removing dependency on df-sb and df-clab (so that it depends on df-clel and df-rex only on top of first-order logic). Prefer its use over bj-rexcom4b when sufficient (in particular when V is substituted for _V ). Note the V in the hypothesis instead of _V . (Contributed by BJ, 14-Sep-2019) (Proof modification is discouraged.)

Ref Expression
Hypothesis bj-rexcom4bv.1 ⊢ B ∈ V
Assertion bj-rexcom4bv ⊢ ∃ x ∃ y ∈ A φ ∧ x = B ↔ ∃ y ∈ A φ

Proof

Step Hyp Ref Expression
1 bj-rexcom4bv.1 ⊢ B ∈ V
2 rexcom4a ⊢ ∃ x ∃ y ∈ A φ ∧ x = B ↔ ∃ y ∈ A φ ∧ ∃ x x = B
3 1 bj-issetiv ⊢ ∃ x x = B
4 3 biantru ⊢ φ ↔ φ ∧ ∃ x x = B
5 4 rexbii ⊢ ∃ y ∈ A φ ↔ ∃ y ∈ A φ ∧ ∃ x x = B
6 2 5 bitr4i ⊢ ∃ x ∃ y ∈ A φ ∧ x = B ↔ ∃ y ∈ A φ