Metamath Proof Explorer


Theorem bj-rexcom4b

Description: Remove from rexcom4b dependency on ax-ext and ax-13 (and on df-or , df-cleq , df-nfc , df-v ). The hypothesis uses V instead of _V (see bj-isseti for the motivation). Use bj-rexcom4bv instead when sufficient (in particular when V is substituted for _V ). (Contributed by BJ, 16-Jun-2019) (Proof modification is discouraged.)

Ref Expression
Hypothesis bj-rexcom4b.1 ⊢ B ∈ V
Assertion bj-rexcom4b ⊢ ∃ x ∃ y ∈ A φ ∧ x = B ↔ ∃ y ∈ A φ

Proof

Step Hyp Ref Expression
1 bj-rexcom4b.1 ⊢ B ∈ V
2 rexcom4a ⊢ ∃ x ∃ y ∈ A φ ∧ x = B ↔ ∃ y ∈ A φ ∧ ∃ x x = B
3 1 bj-isseti ⊢ ∃ x x = B
4 3 biantru ⊢ φ ↔ φ ∧ ∃ x x = B
5 4 rexbii ⊢ ∃ y ∈ A φ ↔ ∃ y ∈ A φ ∧ ∃ x x = B
6 2 5 bitr4i ⊢ ∃ x ∃ y ∈ A φ ∧ x = B ↔ ∃ y ∈ A φ