Metamath Proof Explorer


Theorem bj-ru1

Description: A version of Russell's paradox ru not mentioning the universal class. (see also bj-ru ). (Contributed by BJ, 12-Oct-2019) Remove usage of ax-10 , ax-11 , ax-12 by using eqabbw following BTernaryTau's similar revision of ru . (Revised by BJ, 28-Jun-2025) (Proof modification is discouraged.)

Ref Expression
Assertion bj-ru1 ⊢ ¬ ∃ y y = x | ¬ x ∈ x

Proof

Step Hyp Ref Expression
1 ru0 ⊢ ¬ ∀ z z ∈ y ↔ ¬ z ∈ z
2 id ⊢ x = z → x = z
3 2 2 eleq12d ⊢ x = z → x ∈ x ↔ z ∈ z
4 3 notbid ⊢ x = z → ¬ x ∈ x ↔ ¬ z ∈ z
5 4 eqabbw ⊢ y = x | ¬ x ∈ x ↔ ∀ z z ∈ y ↔ ¬ z ∈ z
6 1 5 mtbir ⊢ ¬ y = x | ¬ x ∈ x
7 6 nex ⊢ ¬ ∃ y y = x | ¬ x ∈ x