Metamath Proof Explorer


Theorem bj-ru1

Description: A version of Russell's paradox ru not mentioning the universal class. (see also bj-ru ). (Contributed by BJ, 12-Oct-2019) Remove usage of ax-10 , ax-11 , ax-12 by using eqabbw following BTernaryTau's similar revision of ru . (Revised by BJ, 28-Jun-2025) (Proof modification is discouraged.)

Ref Expression
Assertion bj-ru1 ¬ ∃ 𝑦 𝑦 = { 𝑥 ∣ ¬ 𝑥 ∈ 𝑥 }

Proof

Step Hyp Ref Expression
1 ru0 ⊢ ¬ ∀ 𝑧 ( 𝑧 ∈ 𝑦 ↔ ¬ 𝑧 ∈ 𝑧 )
2 id ⊢ ( 𝑥 = 𝑧 → 𝑥 = 𝑧 )
3 2 2 eleq12d ⊢ ( 𝑥 = 𝑧 → ( 𝑥 ∈ 𝑥 ↔ 𝑧 ∈ 𝑧 ) )
4 3 notbid ⊢ ( 𝑥 = 𝑧 → ( ¬ 𝑥 ∈ 𝑥 ↔ ¬ 𝑧 ∈ 𝑧 ) )
5 4 eqabbw ⊢ ( 𝑦 = { 𝑥 ∣ ¬ 𝑥 ∈ 𝑥 } ↔ ∀ 𝑧 ( 𝑧 ∈ 𝑦 ↔ ¬ 𝑧 ∈ 𝑧 ) )
6 1 5 mtbir ⊢ ¬ 𝑦 = { 𝑥 ∣ ¬ 𝑥 ∈ 𝑥 }
7 6 nex ⊢ ¬ ∃ 𝑦 𝑦 = { 𝑥 ∣ ¬ 𝑥 ∈ 𝑥 }