Metamath Proof Explorer


Theorem cardidm

Description: The cardinality function is idempotent. Proposition 10.11 of TakeutiZaring p. 85. (Contributed by Mario Carneiro, 7-Jan-2013)

Ref Expression
Assertion cardidm ⊢ card ⁡ card ⁡ A = card ⁡ A

Proof

Step Hyp Ref Expression
1 cardid2 ⊢ A ∈ dom ⁡ card → card ⁡ A ≈ A
2 1 ensymd ⊢ A ∈ dom ⁡ card → A ≈ card ⁡ A
3 entr ⊢ y ≈ A ∧ A ≈ card ⁡ A → y ≈ card ⁡ A
4 3 expcom ⊢ A ≈ card ⁡ A → y ≈ A → y ≈ card ⁡ A
5 2 4 syl ⊢ A ∈ dom ⁡ card → y ≈ A → y ≈ card ⁡ A
6 entr ⊢ y ≈ card ⁡ A ∧ card ⁡ A ≈ A → y ≈ A
7 6 expcom ⊢ card ⁡ A ≈ A → y ≈ card ⁡ A → y ≈ A
8 1 7 syl ⊢ A ∈ dom ⁡ card → y ≈ card ⁡ A → y ≈ A
9 5 8 impbid ⊢ A ∈ dom ⁡ card → y ≈ A ↔ y ≈ card ⁡ A
10 9 rabbidv ⊢ A ∈ dom ⁡ card → y ∈ On | y ≈ A = y ∈ On | y ≈ card ⁡ A
11 10 inteqd ⊢ A ∈ dom ⁡ card → ⋂ y ∈ On | y ≈ A = ⋂ y ∈ On | y ≈ card ⁡ A
12 cardval3 ⊢ A ∈ dom ⁡ card → card ⁡ A = ⋂ y ∈ On | y ≈ A
13 cardon ⊢ card ⁡ A ∈ On
14 oncardval ⊢ card ⁡ A ∈ On → card ⁡ card ⁡ A = ⋂ y ∈ On | y ≈ card ⁡ A
15 13 14 mp1i ⊢ A ∈ dom ⁡ card → card ⁡ card ⁡ A = ⋂ y ∈ On | y ≈ card ⁡ A
16 11 12 15 3eqtr4rd ⊢ A ∈ dom ⁡ card → card ⁡ card ⁡ A = card ⁡ A
17 card0 ⊢ card ⁡ ∅ = ∅
18 ndmfv ⊢ ¬ A ∈ dom ⁡ card → card ⁡ A = ∅
19 18 fveq2d ⊢ ¬ A ∈ dom ⁡ card → card ⁡ card ⁡ A = card ⁡ ∅
20 17 19 18 3eqtr4a ⊢ ¬ A ∈ dom ⁡ card → card ⁡ card ⁡ A = card ⁡ A
21 16 20 pm2.61i ⊢ card ⁡ card ⁡ A = card ⁡ A