Theorem cdlemk5auN

Description: Part of proof of Lemma K of Crawley p. 118. (Contributed by NM, 3-Jul-2013) (New usage is discouraged.)

	Ref	Expression
Hypotheses	cdlemk1.b	$$⊢B={\mathrm{Base}}_K$$
	cdlemk1.l	$$⊢\underset{\dot{}}{\le }={\le }_K$$
	cdlemk1.j	$$⊢\underset{\dot{}}{\vee }=\mathrm{join}\left(K\right)$$
	cdlemk1.m	$$⊢\underset{\dot{}}{\wedge }=\mathrm{meet}\left(K\right)$$
	cdlemk1.a	$$⊢A=\mathrm{Atoms}\left(K\right)$$
	cdlemk1.h	$$⊢H=\mathrm{LHyp}\left(K\right)$$
	cdlemk1.t	$$⊢T=\mathrm{LTrn}\left(K\right)\left(W\right)$$
	cdlemk1.r	$$⊢R=\mathrm{trL}\left(K\right)\left(W\right)$$
	cdlemk1.s	$$⊢S=\left(f\in T⟼\left(\iota i\in T|i\left(P\right)=\left(P\underset{\dot{}}{\vee }R\left(f\right)\right)\underset{\dot{}}{\wedge }\left(N\left(P\right)\underset{\dot{}}{\vee }R\left(f\circ F^{-1}\right)\right)\right)\right)$$
	cdlemk1.o	$$⊢O=S\left(D\right)$$
Assertion	cdlemk5auN	$$⊢\left(\left(K\in \mathrm{HL}\wedge W\in H\right)\wedge \left(D\in T\wedge G\in T\wedge X\in T\right)\wedge \left(R\left(G\right)\ne R\left(D\right)\wedge \left(D\ne {\mathrm{I}\upharpoonright }_B\wedge G\ne {\mathrm{I}\upharpoonright }_B\right)\wedge \left(P\in A\wedge \neg P\underset{\dot{}}{\le }W\right)\right)\right)\to \left(\left(D\left(P\right)\underset{\dot{}}{\vee }R\left(D\right)\right)\underset{\dot{}}{\wedge }\left(D\left(P\right)\underset{\dot{}}{\vee }R\left(G\circ D^{-1}\right)\right)\right)\underset{\dot{}}{\le }\left(X\left(P\right)\underset{\dot{}}{\vee }R\left(X\circ D^{-1}\right)\right)$$

Proof

Step	Hyp	Ref	Expression
1		cdlemk1.b	$$⊢B={\mathrm{Base}}_K$$
2		cdlemk1.l	$$⊢\underset{\dot{}}{\le }={\le }_K$$
3		cdlemk1.j	$$⊢\underset{\dot{}}{\vee }=\mathrm{join}\left(K\right)$$
4		cdlemk1.m	$$⊢\underset{\dot{}}{\wedge }=\mathrm{meet}\left(K\right)$$
5		cdlemk1.a	$$⊢A=\mathrm{Atoms}\left(K\right)$$
6		cdlemk1.h	$$⊢H=\mathrm{LHyp}\left(K\right)$$
7		cdlemk1.t	$$⊢T=\mathrm{LTrn}\left(K\right)\left(W\right)$$
8		cdlemk1.r	$$⊢R=\mathrm{trL}\left(K\right)\left(W\right)$$
9		cdlemk1.s	$$⊢S=\left(f\in T⟼\left(\iota i\in T|i\left(P\right)=\left(P\underset{\dot{}}{\vee }R\left(f\right)\right)\underset{\dot{}}{\wedge }\left(N\left(P\right)\underset{\dot{}}{\vee }R\left(f\circ F^{-1}\right)\right)\right)\right)$$
10		cdlemk1.o	$$⊢O=S\left(D\right)$$
11	1 2 3 5 6 7 8 4	cdlemk5a	$$⊢\left(\left(K\in \mathrm{HL}\wedge W\in H\right)\wedge \left(D\in T\wedge G\in T\wedge X\in T\right)\wedge \left(R\left(G\right)\ne R\left(D\right)\wedge \left(D\ne {\mathrm{I}\upharpoonright }_B\wedge G\ne {\mathrm{I}\upharpoonright }_B\right)\wedge \left(P\in A\wedge \neg P\underset{\dot{}}{\le }W\right)\right)\right)\to \left(\left(D\left(P\right)\underset{\dot{}}{\vee }R\left(D\right)\right)\underset{\dot{}}{\wedge }\left(D\left(P\right)\underset{\dot{}}{\vee }R\left(G\circ D^{-1}\right)\right)\right)\underset{\dot{}}{\le }\left(X\left(P\right)\underset{\dot{}}{\vee }R\left(X\circ D^{-1}\right)\right)$$