Metamath Proof Explorer


Theorem cf0

Description: Value of the cofinality function at 0. Exercise 2 of TakeutiZaring p. 102. (Contributed by NM, 16-Apr-2004)

Ref Expression
Assertion cf0 ⊢ cf ⁡ ∅ = ∅

Proof

Step Hyp Ref Expression
1 cfub ⊢ cf ⁡ ∅ ⊆ ⋂ x | ∃ y x = card ⁡ y ∧ y ⊆ ∅ ∧ ∅ ⊆ ⋃ y
2 0ss ⊢ ∅ ⊆ ⋃ y
3 2 biantru ⊢ y ⊆ ∅ ↔ y ⊆ ∅ ∧ ∅ ⊆ ⋃ y
4 ss0b ⊢ y ⊆ ∅ ↔ y = ∅
5 3 4 bitr3i ⊢ y ⊆ ∅ ∧ ∅ ⊆ ⋃ y ↔ y = ∅
6 5 anbi1ci ⊢ x = card ⁡ y ∧ y ⊆ ∅ ∧ ∅ ⊆ ⋃ y ↔ y = ∅ ∧ x = card ⁡ y
7 6 exbii ⊢ ∃ y x = card ⁡ y ∧ y ⊆ ∅ ∧ ∅ ⊆ ⋃ y ↔ ∃ y y = ∅ ∧ x = card ⁡ y
8 0ex ⊢ ∅ ∈ V
9 fveq2 ⊢ y = ∅ → card ⁡ y = card ⁡ ∅
10 9 eqeq2d ⊢ y = ∅ → x = card ⁡ y ↔ x = card ⁡ ∅
11 8 10 ceqsexv ⊢ ∃ y y = ∅ ∧ x = card ⁡ y ↔ x = card ⁡ ∅
12 card0 ⊢ card ⁡ ∅ = ∅
13 12 eqeq2i ⊢ x = card ⁡ ∅ ↔ x = ∅
14 7 11 13 3bitri ⊢ ∃ y x = card ⁡ y ∧ y ⊆ ∅ ∧ ∅ ⊆ ⋃ y ↔ x = ∅
15 14 abbii ⊢ x | ∃ y x = card ⁡ y ∧ y ⊆ ∅ ∧ ∅ ⊆ ⋃ y = x | x = ∅
16 df-sn ⊢ ∅ = x | x = ∅
17 15 16 eqtr4i ⊢ x | ∃ y x = card ⁡ y ∧ y ⊆ ∅ ∧ ∅ ⊆ ⋃ y = ∅
18 17 inteqi ⊢ ⋂ x | ∃ y x = card ⁡ y ∧ y ⊆ ∅ ∧ ∅ ⊆ ⋃ y = ⋂ ∅
19 8 intsn ⊢ ⋂ ∅ = ∅
20 18 19 eqtri ⊢ ⋂ x | ∃ y x = card ⁡ y ∧ y ⊆ ∅ ∧ ∅ ⊆ ⋃ y = ∅
21 1 20 sseqtri ⊢ cf ⁡ ∅ ⊆ ∅
22 ss0b ⊢ cf ⁡ ∅ ⊆ ∅ ↔ cf ⁡ ∅ = ∅
23 21 22 mpbi ⊢ cf ⁡ ∅ = ∅