Metamath Proof Explorer


Theorem chjcl

Description: Closure of join in CH . (Contributed by NM, 2-Nov-1999) (New usage is discouraged.)

Ref Expression
Assertion chjcl ⊢ A ∈ C ℋ ∧ B ∈ C ℋ → A ∨ ℋ B ∈ C ℋ

Proof

Step Hyp Ref Expression
1 chsh ⊢ A ∈ C ℋ → A ∈ S ℋ
2 chsh ⊢ B ∈ C ℋ → B ∈ S ℋ
3 shjcl ⊢ A ∈ S ℋ ∧ B ∈ S ℋ → A ∨ ℋ B ∈ C ℋ
4 1 2 3 syl2an ⊢ A ∈ C ℋ ∧ B ∈ C ℋ → A ∨ ℋ B ∈ C ℋ