Metamath Proof Explorer


Theorem cjreim2

Description: The conjugate of the representation of a complex number in terms of real and imaginary parts. (Contributed by NM, 1-Jul-2005) (Proof shortened by Mario Carneiro, 29-May-2016)

Ref Expression
Assertion cjreim2 ⊢ A ∈ ℝ ∧ B ∈ ℝ → A − i ⁢ B ‾ = A + i ⁢ B

Proof

Step Hyp Ref Expression
1 cjreim ⊢ A ∈ ℝ ∧ B ∈ ℝ → A + i ⁢ B ‾ = A − i ⁢ B
2 1 fveq2d ⊢ A ∈ ℝ ∧ B ∈ ℝ → A + i ⁢ B ‾ ‾ = A − i ⁢ B ‾
3 simpl ⊢ A ∈ ℝ ∧ B ∈ ℝ → A ∈ ℝ
4 3 recnd ⊢ A ∈ ℝ ∧ B ∈ ℝ → A ∈ ℂ
5 ax-icn ⊢ i ∈ ℂ
6 5 a1i ⊢ A ∈ ℝ ∧ B ∈ ℝ → i ∈ ℂ
7 simpr ⊢ A ∈ ℝ ∧ B ∈ ℝ → B ∈ ℝ
8 7 recnd ⊢ A ∈ ℝ ∧ B ∈ ℝ → B ∈ ℂ
9 6 8 mulcld ⊢ A ∈ ℝ ∧ B ∈ ℝ → i ⁢ B ∈ ℂ
10 4 9 addcld ⊢ A ∈ ℝ ∧ B ∈ ℝ → A + i ⁢ B ∈ ℂ
11 cjcj ⊢ A + i ⁢ B ∈ ℂ → A + i ⁢ B ‾ ‾ = A + i ⁢ B
12 10 11 syl ⊢ A ∈ ℝ ∧ B ∈ ℝ → A + i ⁢ B ‾ ‾ = A + i ⁢ B
13 2 12 eqtr3d ⊢ A ∈ ℝ ∧ B ∈ ℝ → A − i ⁢ B ‾ = A + i ⁢ B