Metamath Proof Explorer


Theorem clsslem

Description: The closure of a subclass is a subclass of the closure. (Contributed by RP, 16-May-2020)

Ref Expression
Assertion clsslem ⊢ R ⊆ S → ⋂ r | R ⊆ r ∧ φ ⊆ ⋂ r | S ⊆ r ∧ φ

Proof

Step Hyp Ref Expression
1 sstr2 ⊢ R ⊆ S → S ⊆ r → R ⊆ r
2 1 anim1d ⊢ R ⊆ S → S ⊆ r ∧ φ → R ⊆ r ∧ φ
3 2 ss2abdv ⊢ R ⊆ S → r | S ⊆ r ∧ φ ⊆ r | R ⊆ r ∧ φ
4 intss ⊢ r | S ⊆ r ∧ φ ⊆ r | R ⊆ r ∧ φ → ⋂ r | R ⊆ r ∧ φ ⊆ ⋂ r | S ⊆ r ∧ φ
5 3 4 syl ⊢ R ⊆ S → ⋂ r | R ⊆ r ∧ φ ⊆ ⋂ r | S ⊆ r ∧ φ