Metamath Proof Explorer


Theorem clsslem

Description: The closure of a subclass is a subclass of the closure. (Contributed by RP, 16-May-2020)

Ref Expression
Assertion clsslem ( 𝑅 ⊆ 𝑆 → ∩ { 𝑟 ∣ ( 𝑅 ⊆ 𝑟 ∧ 𝜑 ) } ⊆ ∩ { 𝑟 ∣ ( 𝑆 ⊆ 𝑟 ∧ 𝜑 ) } )

Proof

Step Hyp Ref Expression
1 sstr2 ⊢ ( 𝑅 ⊆ 𝑆 → ( 𝑆 ⊆ 𝑟 → 𝑅 ⊆ 𝑟 ) )
2 1 anim1d ⊢ ( 𝑅 ⊆ 𝑆 → ( ( 𝑆 ⊆ 𝑟 ∧ 𝜑 ) → ( 𝑅 ⊆ 𝑟 ∧ 𝜑 ) ) )
3 2 ss2abdv ⊢ ( 𝑅 ⊆ 𝑆 → { 𝑟 ∣ ( 𝑆 ⊆ 𝑟 ∧ 𝜑 ) } ⊆ { 𝑟 ∣ ( 𝑅 ⊆ 𝑟 ∧ 𝜑 ) } )
4 intss ⊢ ( { 𝑟 ∣ ( 𝑆 ⊆ 𝑟 ∧ 𝜑 ) } ⊆ { 𝑟 ∣ ( 𝑅 ⊆ 𝑟 ∧ 𝜑 ) } → ∩ { 𝑟 ∣ ( 𝑅 ⊆ 𝑟 ∧ 𝜑 ) } ⊆ ∩ { 𝑟 ∣ ( 𝑆 ⊆ 𝑟 ∧ 𝜑 ) } )
5 3 4 syl ⊢ ( 𝑅 ⊆ 𝑆 → ∩ { 𝑟 ∣ ( 𝑅 ⊆ 𝑟 ∧ 𝜑 ) } ⊆ ∩ { 𝑟 ∣ ( 𝑆 ⊆ 𝑟 ∧ 𝜑 ) } )