Metamath Proof Explorer


Theorem clsss3

Description: The closure of a subset of a topological space is included in the space. (Contributed by NM, 26-Feb-2007)

Ref Expression
Hypothesis clscld.1 ⊢ X = ⋃ J
Assertion clsss3 ⊢ J ∈ Top ∧ S ⊆ X → cls ⁡ J ⁡ S ⊆ X

Proof

Step Hyp Ref Expression
1 clscld.1 ⊢ X = ⋃ J
2 1 clscld ⊢ J ∈ Top ∧ S ⊆ X → cls ⁡ J ⁡ S ∈ Clsd ⁡ J
3 1 cldss ⊢ cls ⁡ J ⁡ S ∈ Clsd ⁡ J → cls ⁡ J ⁡ S ⊆ X
4 2 3 syl ⊢ J ∈ Top ∧ S ⊆ X → cls ⁡ J ⁡ S ⊆ X