Metamath Proof Explorer


Theorem colperp

Description: Deduce a perpendicularity from perpendicularity and colinearity. (Contributed by Thierry Arnoux, 8-Dec-2019)

Ref Expression
Hypotheses colperpex.p ⊢ P = Base G
colperpex.d ⊢ - ˙ = dist ⁡ G
colperpex.i ⊢ I = Itv ⁡ G
colperpex.l ⊢ L = Line 𝒢 ⁡ G
colperpex.g ⊢ φ → G ∈ 𝒢 Tarski
colperp.a ⊢ φ → A ∈ P
colperp.b ⊢ φ → B ∈ P
colperp.c ⊢ φ → C ∈ P
colperp.1 ⊢ φ → A L B ⟂ 𝒢 ⁡ G D
colperp.2 ⊢ φ → C ∈ A L B ∨ A = B
colperp.3 ⊢ φ → A ≠ C
Assertion colperp ⊢ φ → A L C ⟂ 𝒢 ⁡ G D

Proof

Step Hyp Ref Expression
1 colperpex.p ⊢ P = Base G
2 colperpex.d ⊢ - ˙ = dist ⁡ G
3 colperpex.i ⊢ I = Itv ⁡ G
4 colperpex.l ⊢ L = Line 𝒢 ⁡ G
5 colperpex.g ⊢ φ → G ∈ 𝒢 Tarski
6 colperp.a ⊢ φ → A ∈ P
7 colperp.b ⊢ φ → B ∈ P
8 colperp.c ⊢ φ → C ∈ P
9 colperp.1 ⊢ φ → A L B ⟂ 𝒢 ⁡ G D
10 colperp.2 ⊢ φ → C ∈ A L B ∨ A = B
11 colperp.3 ⊢ φ → A ≠ C
12 4 5 9 perpln1 ⊢ φ → A L B ∈ ran ⁡ L
13 1 3 4 5 6 7 12 tglnne ⊢ φ → A ≠ B
14 1 3 4 5 6 7 13 tglinerflx1 ⊢ φ → A ∈ A L B
15 13 neneqd ⊢ φ → ¬ A = B
16 10 orcomd ⊢ φ → A = B ∨ C ∈ A L B
17 16 ord ⊢ φ → ¬ A = B → C ∈ A L B
18 15 17 mpd ⊢ φ → C ∈ A L B
19 1 3 4 5 6 8 11 11 12 14 18 tglinethru ⊢ φ → A L B = A L C
20 19 9 eqbrtrrd ⊢ φ → A L C ⟂ 𝒢 ⁡ G D