Metamath Proof Explorer


Definition df-coe

Description: Define the coefficient function for a polynomial. (Contributed by Mario Carneiro, 22-Jul-2014)

Ref Expression
Assertion df-coe ⊢ coeff = f ∈ Poly ⁡ ℂ ⟼ ι a ∈ ℂ ℕ 0 | ∃ n ∈ ℕ 0 a ℤ ≥ n + 1 = 0 ∧ f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k

Detailed syntax breakdown

Step Hyp Ref Expression
0 ccoe class coeff
1 vf setvar f
2 cply class Poly
3 cc class ℂ
4 3 2 cfv class Poly ⁡ ℂ
5 va setvar a
6 cmap class ↑ 𝑚
7 cn0 class ℕ 0
8 3 7 6 co class ℂ ℕ 0
9 vn setvar n
10 5 cv setvar a
11 cuz class ℤ ≥
12 9 cv setvar n
13 caddc class +
14 c1 class 1
15 12 14 13 co class n + 1
16 15 11 cfv class ℤ ≥ n + 1
17 10 16 cima class a ℤ ≥ n + 1
18 cc0 class 0
19 18 csn class 0
20 17 19 wceq wff a ℤ ≥ n + 1 = 0
21 1 cv setvar f
22 vz setvar z
23 vk setvar k
24 cfz class …
25 18 12 24 co class 0 … n
26 23 cv setvar k
27 26 10 cfv class a ⁡ k
28 cmul class ×
29 22 cv setvar z
30 cexp class ^
31 29 26 30 co class z k
32 27 31 28 co class a ⁡ k ⁢ z k
33 25 32 23 csu class ∑ k = 0 n a ⁡ k ⁢ z k
34 22 3 33 cmpt class z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
35 21 34 wceq wff f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
36 20 35 wa wff a ℤ ≥ n + 1 = 0 ∧ f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
37 36 9 7 wrex wff ∃ n ∈ ℕ 0 a ℤ ≥ n + 1 = 0 ∧ f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
38 37 5 8 crio class ι a ∈ ℂ ℕ 0 | ∃ n ∈ ℕ 0 a ℤ ≥ n + 1 = 0 ∧ f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
39 1 4 38 cmpt class f ∈ Poly ⁡ ℂ ⟼ ι a ∈ ℂ ℕ 0 | ∃ n ∈ ℕ 0 a ℤ ≥ n + 1 = 0 ∧ f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
40 0 39 wceq wff coeff = f ∈ Poly ⁡ ℂ ⟼ ι a ∈ ℂ ℕ 0 | ∃ n ∈ ℕ 0 a ℤ ≥ n + 1 = 0 ∧ f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k