Metamath Proof Explorer


Theorem dfss

Description: Variant of subclass definition dfss2 . (Contributed by NM, 21-Jun-1993)

Ref Expression
Assertion dfss ⊢ A ⊆ B ↔ A = A ∩ B

Proof

Step Hyp Ref Expression
1 dfss2 ⊢ A ⊆ B ↔ A ∩ B = A
2 eqcom ⊢ A ∩ B = A ↔ A = A ∩ B
3 1 2 bitri ⊢ A ⊆ B ↔ A = A ∩ B