Metamath Proof Explorer


Theorem dgraaf

Description: Degree function on algebraic numbers is a function. (Contributed by Stefan O'Rear, 25-Nov-2014) (Proof shortened by AV, 29-Sep-2020)

Ref Expression
Assertion dgraaf ⊢ deg 𝔸 : 𝔸 ⟶ ℕ

Proof

Step Hyp Ref Expression
1 ltso ⊢ < Or ℝ
2 1 infex ⊢ inf b ∈ ℕ | ∃ p ∈ Poly ⁡ ℚ ∖ 0 𝑝 deg ⁡ p = b ∧ p ⁡ a = 0 ℝ < ∈ V
3 df-dgraa ⊢ deg 𝔸 = a ∈ 𝔸 ⟼ inf b ∈ ℕ | ∃ p ∈ Poly ⁡ ℚ ∖ 0 𝑝 deg ⁡ p = b ∧ p ⁡ a = 0 ℝ <
4 2 3 fnmpti ⊢ deg 𝔸 Fn 𝔸
5 dgraacl ⊢ a ∈ 𝔸 → deg 𝔸 ⁡ a ∈ ℕ
6 5 rgen ⊢ ∀ a ∈ 𝔸 deg 𝔸 ⁡ a ∈ ℕ
7 ffnfv ⊢ deg 𝔸 : 𝔸 ⟶ ℕ ↔ deg 𝔸 Fn 𝔸 ∧ ∀ a ∈ 𝔸 deg 𝔸 ⁡ a ∈ ℕ
8 4 6 7 mpbir2an ⊢ deg 𝔸 : 𝔸 ⟶ ℕ