Metamath Proof Explorer


Theorem discsubclem

Description: Lemma for discsubc . (Contributed by Zhi Wang, 1-Nov-2025)

Ref Expression
Hypothesis discsubc.j ⊢ J = x ∈ S , y ∈ S ⟼ if x = y I ⁡ x ∅
Assertion discsubclem ⊢ J Fn S × S

Proof

Step Hyp Ref Expression
1 discsubc.j ⊢ J = x ∈ S , y ∈ S ⟼ if x = y I ⁡ x ∅
2 snex ⊢ I ⁡ x ∈ V
3 0ex ⊢ ∅ ∈ V
4 2 3 ifex ⊢ if x = y I ⁡ x ∅ ∈ V
5 1 4 fnmpoi ⊢ J Fn S × S