Metamath Proof Explorer


Theorem discsubclem

Description: Lemma for discsubc . (Contributed by Zhi Wang, 1-Nov-2025)

Ref Expression
Hypothesis discsubc.j ⊢ 𝐽 = ( 𝑥 ∈ 𝑆 , 𝑦 ∈ 𝑆 ↦ if ( 𝑥 = 𝑦 , { ( 𝐼 ‘ 𝑥 ) } , ∅ ) )
Assertion discsubclem 𝐽 Fn ( 𝑆 × 𝑆 )

Proof

Step Hyp Ref Expression
1 discsubc.j ⊢ 𝐽 = ( 𝑥 ∈ 𝑆 , 𝑦 ∈ 𝑆 ↦ if ( 𝑥 = 𝑦 , { ( 𝐼 ‘ 𝑥 ) } , ∅ ) )
2 snex ⊢ { ( 𝐼 ‘ 𝑥 ) } ∈ V
3 0ex ⊢ ∅ ∈ V
4 2 3 ifex ⊢ if ( 𝑥 = 𝑦 , { ( 𝐼 ‘ 𝑥 ) } , ∅ ) ∈ V
5 1 4 fnmpoi ⊢ 𝐽 Fn ( 𝑆 × 𝑆 )