Metamath Proof Explorer


Theorem disjabso

Description: Disjointness is absolute for transitive models. Compare Example I.16.3 of Kunen2 p. 96 and the following discussion. (Contributed by Eric Schmidt, 19-Oct-2025)

Ref Expression
Assertion disjabso ⊢ Tr ⁡ M ∧ A ∈ M → A ∩ B = ∅ ↔ ∀ x ∈ M x ∈ A → ¬ x ∈ B

Proof

Step Hyp Ref Expression
1 disj ⊢ A ∩ B = ∅ ↔ ∀ x ∈ A ¬ x ∈ B
2 ralabso ⊢ Tr ⁡ M ∧ A ∈ M → ∀ x ∈ A ¬ x ∈ B ↔ ∀ x ∈ M x ∈ A → ¬ x ∈ B
3 1 2 bitrid ⊢ Tr ⁡ M ∧ A ∈ M → A ∩ B = ∅ ↔ ∀ x ∈ M x ∈ A → ¬ x ∈ B