Metamath Proof Explorer


Theorem disjdmqseqeq1

Description: Lemma for the equality theorem for partition parteq1 . (Contributed by Peter Mazsa, 5-Oct-2021)

Ref Expression
Assertion disjdmqseqeq1 R=SDisjRdomR/R=ADisjSdomS/S=A

Proof

Step Hyp Ref Expression
1 disjeq R=SDisjRDisjS
2 dmqseqeq1 R=SdomR/R=AdomS/S=A
3 1 2 anbi12d R=SDisjRdomR/R=ADisjSdomS/S=A