Theorem disjimres

Description: Disjointness condition for restriction. (Contributed by Peter Mazsa, 27-Sep-2021)

	Ref	Expression
Assertion	disjimres	$$⊢DisjR\to Disj\left({R\upharpoonright }_A\right)$$

Proof

Step	Hyp	Ref	Expression
1		resss	$$⊢{R\upharpoonright }_A\subseteq R$$
2	1	disjssi	$$⊢DisjR\to Disj\left({R\upharpoonright }_A\right)$$