Metamath Proof Explorer


Theorem disjimres

Description: Disjointness condition for restriction. (Contributed by Peter Mazsa, 27-Sep-2021)

Ref Expression
Assertion disjimres ( Disj 𝑅 → Disj ( 𝑅𝐴 ) )

Proof

Step Hyp Ref Expression
1 resss ( 𝑅𝐴 ) ⊆ 𝑅
2 1 disjssi ( Disj 𝑅 → Disj ( 𝑅𝐴 ) )