Metamath Proof Explorer


Theorem disjimxrn

Description: Disjointness condition for range Cartesian product. (Contributed by Peter Mazsa, 15-Dec-2020) (Revised by Peter Mazsa, 22-Sep-2021)

Ref Expression
Assertion disjimxrn ⊢ Disj S → Disj R ⋉ S

Proof

Step Hyp Ref Expression
1 disjorimxrn ⊢ Disj R ∨ Disj S → Disj R ⋉ S
2 1 olcs ⊢ Disj S → Disj R ⋉ S