Metamath Proof Explorer


Theorem divasszi

Description: An associative law for division. (Contributed by NM, 12-Aug-1999)

Ref Expression
Hypotheses divclz.1 ⊢ A ∈ ℂ
divclz.2 ⊢ B ∈ ℂ
divmulz.3 ⊢ C ∈ ℂ
Assertion divasszi ⊢ C ≠ 0 → A ⁢ B C = A ⁢ B C

Proof

Step Hyp Ref Expression
1 divclz.1 ⊢ A ∈ ℂ
2 divclz.2 ⊢ B ∈ ℂ
3 divmulz.3 ⊢ C ∈ ℂ
4 divass ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ C ≠ 0 → A ⁢ B C = A ⁢ B C
5 1 2 4 mp3an12 ⊢ C ∈ ℂ ∧ C ≠ 0 → A ⁢ B C = A ⁢ B C
6 3 5 mpan ⊢ C ≠ 0 → A ⁢ B C = A ⁢ B C