Metamath Proof Explorer


Theorem divmulzi

Description: Relationship between division and multiplication. (Contributed by NM, 8-May-1999) (Revised by Mario Carneiro, 17-Feb-2014)

Ref Expression
Hypotheses divclz.1 ⊢ A ∈ ℂ
divclz.2 ⊢ B ∈ ℂ
divmulz.3 ⊢ C ∈ ℂ
Assertion divmulzi ⊢ B ≠ 0 → A B = C ↔ B ⁢ C = A

Proof

Step Hyp Ref Expression
1 divclz.1 ⊢ A ∈ ℂ
2 divclz.2 ⊢ B ∈ ℂ
3 divmulz.3 ⊢ C ∈ ℂ
4 divmul ⊢ A ∈ ℂ ∧ C ∈ ℂ ∧ B ∈ ℂ ∧ B ≠ 0 → A B = C ↔ B ⁢ C = A
5 1 3 4 mp3an12 ⊢ B ∈ ℂ ∧ B ≠ 0 → A B = C ↔ B ⁢ C = A
6 2 5 mpan ⊢ B ≠ 0 → A B = C ↔ B ⁢ C = A