Metamath Proof Explorer


Theorem divscld

Description: Surreal division closure law. (Contributed by Scott Fenton, 16-Mar-2025)

Ref Expression
Hypotheses divscld.1 ⊢ φ → A ∈ No
divscld.2 ⊢ φ → B ∈ No
divscld.3 ⊢ φ → B ≠ 0 s
Assertion divscld ⊢ φ → A / su B ∈ No

Proof

Step Hyp Ref Expression
1 divscld.1 ⊢ φ → A ∈ No
2 divscld.2 ⊢ φ → B ∈ No
3 divscld.3 ⊢ φ → B ≠ 0 s
4 divscl ⊢ A ∈ No ∧ B ∈ No ∧ B ≠ 0 s → A / su B ∈ No
5 1 2 3 4 syl3anc ⊢ φ → A / su B ∈ No