Metamath Proof Explorer


Theorem djuin

Description: The images of any classes under right and left injection produce disjoint sets. (Contributed by Jim Kingdon, 21-Jun-2022)

Ref Expression
Assertion djuin ⊢ inl A ∩ inr B = ∅

Proof

Step Hyp Ref Expression
1 incom ⊢ inr B ∩ inl A = inl A ∩ inr B
2 imassrn ⊢ inr B ⊆ ran ⁡ inr
3 djurf1o ⊢ inr : V ⟶ 1-1 onto 1 𝑜 × V
4 f1of ⊢ inr : V ⟶ 1-1 onto 1 𝑜 × V → inr : V ⟶ 1 𝑜 × V
5 frn ⊢ inr : V ⟶ 1 𝑜 × V → ran ⁡ inr ⊆ 1 𝑜 × V
6 3 4 5 mp2b ⊢ ran ⁡ inr ⊆ 1 𝑜 × V
7 2 6 sstri ⊢ inr B ⊆ 1 𝑜 × V
8 incom ⊢ inl A ∩ 1 𝑜 × V = 1 𝑜 × V ∩ inl A
9 imassrn ⊢ inl A ⊆ ran ⁡ inl
10 djulf1o ⊢ inl : V ⟶ 1-1 onto ∅ × V
11 f1of ⊢ inl : V ⟶ 1-1 onto ∅ × V → inl : V ⟶ ∅ × V
12 frn ⊢ inl : V ⟶ ∅ × V → ran ⁡ inl ⊆ ∅ × V
13 10 11 12 mp2b ⊢ ran ⁡ inl ⊆ ∅ × V
14 9 13 sstri ⊢ inl A ⊆ ∅ × V
15 1n0 ⊢ 1 𝑜 ≠ ∅
16 15 necomi ⊢ ∅ ≠ 1 𝑜
17 disjsn2 ⊢ ∅ ≠ 1 𝑜 → ∅ ∩ 1 𝑜 = ∅
18 xpdisj1 ⊢ ∅ ∩ 1 𝑜 = ∅ → ∅ × V ∩ 1 𝑜 × V = ∅
19 16 17 18 mp2b ⊢ ∅ × V ∩ 1 𝑜 × V = ∅
20 ssdisj ⊢ inl A ⊆ ∅ × V ∧ ∅ × V ∩ 1 𝑜 × V = ∅ → inl A ∩ 1 𝑜 × V = ∅
21 14 19 20 mp2an ⊢ inl A ∩ 1 𝑜 × V = ∅
22 8 21 eqtr3i ⊢ 1 𝑜 × V ∩ inl A = ∅
23 ssdisj ⊢ inr B ⊆ 1 𝑜 × V ∧ 1 𝑜 × V ∩ inl A = ∅ → inr B ∩ inl A = ∅
24 7 22 23 mp2an ⊢ inr B ∩ inl A = ∅
25 1 24 eqtr3i ⊢ inl A ∩ inr B = ∅