Metamath Proof Explorer


Theorem dmeq

Description: Equality theorem for domain. (Contributed by NM, 11-Aug-1994)

Ref Expression
Assertion dmeq A=BdomA=domB

Proof

Step Hyp Ref Expression
1 dmss ABdomAdomB
2 dmss BAdomBdomA
3 1 2 anim12i ABBAdomAdomBdomBdomA
4 eqss A=BABBA
5 eqss domA=domBdomAdomBdomBdomA
6 3 4 5 3imtr4i A=BdomA=domB