Metamath Proof Explorer


Theorem dmss

Description: Subset theorem for domain. (Contributed by NM, 11-Aug-1994)

Ref Expression
Assertion dmss ⊢ A ⊆ B → dom ⁡ A ⊆ dom ⁡ B

Proof

Step Hyp Ref Expression
1 ssel ⊢ A ⊆ B → x y ∈ A → x y ∈ B
2 1 eximdv ⊢ A ⊆ B → ∃ y x y ∈ A → ∃ y x y ∈ B
3 vex ⊢ x ∈ V
4 3 eldm2 ⊢ x ∈ dom ⁡ A ↔ ∃ y x y ∈ A
5 3 eldm2 ⊢ x ∈ dom ⁡ B ↔ ∃ y x y ∈ B
6 2 4 5 3imtr4g ⊢ A ⊆ B → x ∈ dom ⁡ A → x ∈ dom ⁡ B
7 6 ssrdv ⊢ A ⊆ B → dom ⁡ A ⊆ dom ⁡ B