Metamath Proof Explorer


Theorem ssrdv

Description: Deduction based on subclass definition. (Contributed by NM, 15-Nov-1995)

Ref Expression
Hypothesis ssrdv.1 ⊢ φ → x ∈ A → x ∈ B
Assertion ssrdv ⊢ φ → A ⊆ B

Proof

Step Hyp Ref Expression
1 ssrdv.1 ⊢ φ → x ∈ A → x ∈ B
2 1 alrimiv ⊢ φ → ∀ x x ∈ A → x ∈ B
3 df-ss ⊢ A ⊆ B ↔ ∀ x x ∈ A → x ∈ B
4 2 3 sylibr ⊢ φ → A ⊆ B