Metamath Proof Explorer


Theorem ecase2d

Description: Deduction for elimination by cases. (Contributed by NM, 21-Apr-1994) (Proof shortened by Wolf Lammen, 19-Sep-2024)

Ref Expression
Hypotheses ecase2d.1 φψ
ecase2d.2 φ¬ψχ
ecase2d.3 φ¬ψθ
ecase2d.4 φτχθ
Assertion ecase2d φτ

Proof

Step Hyp Ref Expression
1 ecase2d.1 φψ
2 ecase2d.2 φ¬ψχ
3 ecase2d.3 φ¬ψθ
4 ecase2d.4 φτχθ
5 1 2 mpnanrd φ¬χ
6 1 3 mpnanrd φ¬θ
7 4 ord φ¬τχθ
8 5 6 7 mtord φ¬¬τ
9 8 notnotrd φτ