Metamath Proof Explorer


Theorem ecase33d

Description: Deduction for elimination by cases. (Contributed by Thierry Arnoux, 5-Jul-2026)

Ref Expression
Hypotheses ecase33d.1 φ ¬ ψ
ecase33d.2 φ ¬ χ
ecase33d.3 φ ψ χ θ
Assertion ecase33d φ θ

Proof

Step Hyp Ref Expression
1 ecase33d.1 φ ¬ ψ
2 ecase33d.2 φ ¬ χ
3 ecase33d.3 φ ψ χ θ
4 df-3or ψ χ θ ψ χ θ
5 3 4 sylib φ ψ χ θ
6 ioran ¬ ψ χ ¬ ψ ¬ χ
7 1 2 6 sylanbrc φ ¬ ψ χ
8 5 7 orcnd φ θ