Metamath Proof Explorer


Theorem ecase3ad

Description: Deduction for elimination by cases. (Contributed by NM, 24-May-2013)

Ref Expression
Hypotheses ecase3ad.1 φ ψ θ
ecase3ad.2 φ χ θ
ecase3ad.3 φ ¬ ψ ¬ χ θ
Assertion ecase3ad φ θ

Proof

Step Hyp Ref Expression
1 ecase3ad.1 φ ψ θ
2 ecase3ad.2 φ χ θ
3 ecase3ad.3 φ ¬ ψ ¬ χ θ
4 notnotr ¬ ¬ ψ ψ
5 4 1 syl5 φ ¬ ¬ ψ θ
6 notnotr ¬ ¬ χ χ
7 6 2 syl5 φ ¬ ¬ χ θ
8 5 7 3 ecased φ θ