Metamath Proof Explorer
		
		
		
		Description:  Deduction for elimination by cases.  (Contributed by NM, 24-May-2013)
       (Proof shortened by Wolf Lammen, 20-Sep-2024)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypotheses | ecase3ad.1 |  | 
					
						|  |  | ecase3ad.2 |  | 
					
						|  |  | ecase3ad.3 |  | 
				
					|  | Assertion | ecase3ad |  | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | ecase3ad.1 |  | 
						
							| 2 |  | ecase3ad.2 |  | 
						
							| 3 |  | ecase3ad.3 |  | 
						
							| 4 | 1 | imp |  | 
						
							| 5 | 2 | imp |  | 
						
							| 6 | 3 | imp |  | 
						
							| 7 | 4 5 6 | pm2.61ddan |  |