Metamath Proof Explorer


Theorem ef2pi

Description: The exponential of 2pi i is 1 . (Contributed by Mario Carneiro, 9-May-2014)

Ref Expression
Assertion ef2pi ⊢ e i ⁢ 2 ⁢ π = 1

Proof

Step Hyp Ref Expression
1 2cn ⊢ 2 ∈ ℂ
2 picn ⊢ π ∈ ℂ
3 1 2 mulcli ⊢ 2 ⁢ π ∈ ℂ
4 efival ⊢ 2 ⁢ π ∈ ℂ → e i ⁢ 2 ⁢ π = cos ⁡ 2 ⁢ π + i ⁢ sin ⁡ 2 ⁢ π
5 3 4 ax-mp ⊢ e i ⁢ 2 ⁢ π = cos ⁡ 2 ⁢ π + i ⁢ sin ⁡ 2 ⁢ π
6 cos2pi ⊢ cos ⁡ 2 ⁢ π = 1
7 sin2pi ⊢ sin ⁡ 2 ⁢ π = 0
8 7 oveq2i ⊢ i ⁢ sin ⁡ 2 ⁢ π = i ⋅ 0
9 it0e0 ⊢ i ⋅ 0 = 0
10 8 9 eqtri ⊢ i ⁢ sin ⁡ 2 ⁢ π = 0
11 6 10 oveq12i ⊢ cos ⁡ 2 ⁢ π + i ⁢ sin ⁡ 2 ⁢ π = 1 + 0
12 1p0e1 ⊢ 1 + 0 = 1
13 11 12 eqtri ⊢ cos ⁡ 2 ⁢ π + i ⁢ sin ⁡ 2 ⁢ π = 1
14 5 13 eqtri ⊢ e i ⁢ 2 ⁢ π = 1