Metamath Proof Explorer


Theorem elcnvrefrelsrel

Description: For sets, being an element of the class of converse reflexive relations ( df-cnvrefrels ) is equivalent to satisfying the converse reflexive relation predicate. (Contributed by Peter Mazsa, 25-Jul-2021)

Ref Expression
Assertion elcnvrefrelsrel ⊢ R ∈ V → R ∈ CnvRefRels ↔ CnvRefRel R

Proof

Step Hyp Ref Expression
1 elrelsrel ⊢ R ∈ V → R ∈ Rels ↔ Rel ⁡ R
2 1 anbi2d ⊢ R ∈ V → R ⊆ I ∩ dom ⁡ R × ran ⁡ R ∧ R ∈ Rels ↔ R ⊆ I ∩ dom ⁡ R × ran ⁡ R ∧ Rel ⁡ R
3 elcnvrefrels2 ⊢ R ∈ CnvRefRels ↔ R ⊆ I ∩ dom ⁡ R × ran ⁡ R ∧ R ∈ Rels
4 dfcnvrefrel2 ⊢ CnvRefRel R ↔ R ⊆ I ∩ dom ⁡ R × ran ⁡ R ∧ Rel ⁡ R
5 2 3 4 3bitr4g ⊢ R ∈ V → R ∈ CnvRefRels ↔ CnvRefRel R