Metamath Proof Explorer


Theorem eldifsni

Description: Membership in a set with an element removed. (Contributed by NM, 10-Mar-2015)

Ref Expression
Assertion eldifsni ⊢ A ∈ B ∖ C → A ≠ C

Proof

Step Hyp Ref Expression
1 eldifsn ⊢ A ∈ B ∖ C ↔ A ∈ B ∧ A ≠ C
2 1 simprbi ⊢ A ∈ B ∖ C → A ≠ C