Metamath Proof Explorer


Theorem eldmcnv

Description: Elementhood in a domain of a converse. (Contributed by Peter Mazsa, 25-May-2018)

Ref Expression
Assertion eldmcnv ⊢ A ∈ V → A ∈ dom ⁡ R -1 ↔ ∃ u u R A

Proof

Step Hyp Ref Expression
1 eldmg ⊢ A ∈ V → A ∈ dom ⁡ R -1 ↔ ∃ u A R -1 u
2 brcnvg ⊢ A ∈ V ∧ u ∈ V → A R -1 u ↔ u R A
3 2 elvd ⊢ A ∈ V → A R -1 u ↔ u R A
4 3 exbidv ⊢ A ∈ V → ∃ u A R -1 u ↔ ∃ u u R A
5 1 4 bitrd ⊢ A ∈ V → A ∈ dom ⁡ R -1 ↔ ∃ u u R A