Metamath Proof Explorer


Theorem eleq1

Description: Equality implies equivalence of membership. (Contributed by NM, 26-May-1993) (Proof shortened by Wolf Lammen, 20-Nov-2019)

Ref Expression
Assertion eleq1 A = B A C B C

Proof

Step Hyp Ref Expression
1 id A = B A = B
2 1 eleq1d A = B A C B C