Metamath Proof Explorer


Theorem eleq1

Description: Equality implies equivalence of membership. (Contributed by NM, 26-May-1993) (Proof shortened by Wolf Lammen, 20-Nov-2019)

Ref Expression
Assertion eleq1 ⊢ A = B → A ∈ C ↔ B ∈ C

Proof

Step Hyp Ref Expression
1 id ⊢ A = B → A = B
2 1 eleq1d ⊢ A = B → A ∈ C ↔ B ∈ C