Metamath Proof Explorer


Theorem elfunsg

Description: Closed form of elfuns . (Contributed by Scott Fenton, 2-May-2014)

Ref Expression
Assertion elfunsg FVF𝖥𝗎𝗇𝗌FunF

Proof

Step Hyp Ref Expression
1 eleq1 f=Ff𝖥𝗎𝗇𝗌F𝖥𝗎𝗇𝗌
2 funeq f=FFunfFunF
3 vex fV
4 3 elfuns f𝖥𝗎𝗇𝗌Funf
5 1 2 4 vtoclbg FVF𝖥𝗎𝗇𝗌FunF