Metamath Proof Explorer


Theorem elpglem2

Description: Lemma for elpg . (Contributed by Emmett Weisz, 28-Aug-2021)

Ref Expression
Assertion elpglem2 1stAPg2ndAPgxxPg1stA𝒫x2ndA𝒫x

Proof

Step Hyp Ref Expression
1 fvex 1stAV
2 fvex 2ndAV
3 1 2 unex 1stA2ndAV
4 3 isseti xx=1stA2ndA
5 sseq1 x=1stA2ndAxPg1stA2ndAPg
6 unss 1stAPg2ndAPg1stA2ndAPg
7 5 6 bitr4di x=1stA2ndAxPg1stAPg2ndAPg
8 7 biimprd x=1stA2ndA1stAPg2ndAPgxPg
9 ssun1 1stA1stA2ndA
10 id x=1stA2ndAx=1stA2ndA
11 9 10 sseqtrrid x=1stA2ndA1stAx
12 vex xV
13 12 elpw2 1stA𝒫x1stAx
14 11 13 sylibr x=1stA2ndA1stA𝒫x
15 ssun2 2ndA1stA2ndA
16 15 10 sseqtrrid x=1stA2ndA2ndAx
17 12 elpw2 2ndA𝒫x2ndAx
18 16 17 sylibr x=1stA2ndA2ndA𝒫x
19 14 18 jca x=1stA2ndA1stA𝒫x2ndA𝒫x
20 8 19 jctird x=1stA2ndA1stAPg2ndAPgxPg1stA𝒫x2ndA𝒫x
21 4 20 eximii x1stAPg2ndAPgxPg1stA𝒫x2ndA𝒫x
22 21 19.37iv 1stAPg2ndAPgxxPg1stA𝒫x2ndA𝒫x