Metamath Proof Explorer


Theorem sseqtrrid

Description: Subclass transitivity deduction. (Contributed by Jonathan Ben-Naim, 3-Jun-2011)

Ref Expression
Hypotheses sseqtrrid.1 ⊢ B ⊆ A
sseqtrrid.2 ⊢ φ → C = A
Assertion sseqtrrid ⊢ φ → B ⊆ C

Proof

Step Hyp Ref Expression
1 sseqtrrid.1 ⊢ B ⊆ A
2 sseqtrrid.2 ⊢ φ → C = A
3 2 eqcomd ⊢ φ → A = C
4 1 3 sseqtrid ⊢ φ → B ⊆ C